Standard Form of :

y= -2(x-3)(x+5)

Multiply it out

y= -2x²-4x+30

In Vertex Form

How do you find it's vertex and intercepts?

y= 2(x-3)²-8

Vertex: (3, -8)

Y-int: make x= 0

X-int: make y= 0

-b  +/-  √b²- 4(a)(c)

How do you change standard form to vertex form?

y= -2x²+12x-15

1. Find the Vertex (3,3)

2. y= a (x-3)²+3

3. Find "a"

4. a= 0

y=(x-3)²+3

Whats the name of each parabola form below?

1. y= ax²+bx+c

2. y= a(x-h)²+k

3. y= a(x-m)(x-n)

1. standard

2. vertex

3. factored

Describe the significance of each pink part of the equation

y= 3(x+5)²-7

3= steep

5= left 5

-7= down 7

Quadratic Equation:

discriminant < 0

no x- int 

(2 imaginary solutions)

Quadratic Equation:

discriminant= 0

1 solution

Quadratic equation:

discriminant>0

2 solutions

Simplify:

3i(2i-5)

Simplify:

√-49

7i

Simplify:

(2i-3)²

5-12i

Simplify:

√150

5√6

How would you find the vertex of:

y= ax²+bx+c

y- intercept of:

ax²+bx+c

make x=0

y-int is "c"

Whats the x-intercept of

ax²+bx+c?

make y= 0

or factor or use the quadratic formula