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a square matrix whose determinant is zero |
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If A(inverse) exists then Ax=b has the unique solution: |
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A nxn matrix is invertible if and only if... |
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maximum number of independent rows/columns |
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If AB is invertible, then... |
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both A and B are invertible |
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defined only for square matrices |
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determinant of the square matrix formed by deleting one row and one column from some larger square matrix |
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add all of these to get the determinant |
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MOST IMPORTANT: If a subset S of a vector space V fails to contain the zero vector, then it cannot form a subspace Next: check if it is closed under addition and then scalar multiplication |
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put in row echelon form and find columns with leading 1's
*need at least n vectors to span R^n and need to be linearly independent |
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The vectors are linearly dependent if... |
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the equation has a solution (equal to zero) then at least one of the scalars (ai) is not zero
determinant = 0
a set of n+1 or more vectors in R^n, since dim = n
if there are any free variables |
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To check linear dependence/independence |
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put set of vectors in row echelon form |
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A set of only one vector is linearly independent if and only if that one vector is... |
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a set containing two vectors is linearly independent so long as... |
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one vector is not a multiple of the other |
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a set containing the zero vector is always |
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# of vectors in any basis for V = # of free variables |
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ALWAYS: linearly independent and span V |
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dimension of the column space = |
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Let A be an nun matrix. The set of column vectors of A corresponding to those column vectors containing leading ones in any row-echelon form of A is a basis for colspace (A). |
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The set of nonzero row vectors in any row-echelon form of an mxn matrix A is a basis for rowspace (A) |
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find reduced row echelon form -> then find free variable -> vectors multiplied to those free variables are the span of the nullspace -> if linearly independent then a basis as well! |
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when giving example of bases of R^n |
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give standard, then multiply any of them with a number and still a basis! |
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