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a^2 + b^2 = c^2
where c is the hypotenuse |
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midpoint = ((x1+x2)/2, (y1+y2)/2) |
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ley y be zero and solve the equation for x |
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let X be zero and solve the equation for y |
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A graph is symmetric with respect to the x-axis if |
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A graph is symmetric with respect to the y-axis if |
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A graph is symmetric with respect to the origin if |
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Standard form of the equation of a circle |
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√((x-h)^2 + (y-k)^2) = r
where r is the radius and (h,k) is the center |
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Slope-intercept form of the equation of a line |
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y = mx + b
where m is the slope and b is the y-intercept |
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The slope of a line passing through two points |
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m = (y2-y1)/(x2-x1)
where x1 ≠ x2 |
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Point- slope form of the equation of a line |
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y - y1 = m(x - x1)
where m is the slope and (x1, y1) is a point on the graph |
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Two lines are parallel if |
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Two lines are perpendicular if |
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for every x input values there is only one y output |
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tests if the graph is a function or not (if a vertical line drawn anywhere on the graph hits the graph more than once it is not a function) |
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When finding the domain and range of a function, what is the difference between ( ) and [ ]? |
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Parentheses do not include that point, whereas brackets do. |
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The zeros of a function f(x) are |
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the x values for which f(x) = 0 |
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A function f(x) is even if |
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for each x in the domain of f, f(-x) = f(x)
[symmetric with respect to the y-axis] |
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A function f(x) is odd if |
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for each X in the domain of f, f(-x) = -f(x)
[symmetric with respect to the origin] |
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Vertical shift c units upward |
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Vertical shift c units downward |
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Horizontal shift c units to the right |
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Horizontal shift c units to the left |
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Is g(x) the inverse of f(x)? |
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If f(g(x)) = x for every x in the domain of g AND g(f(x)) = x for every x in the domain of f. |
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Only ? functions have an inverse |
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One-to-one functions (for every x there is only one y) |
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tests whether the graph has an inverse (if a horizontal line drawn anywhere on the graph touches the graph more than once it does not have an inverse) |
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To find the inverse function of f(x) |
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1. First verify that there is an inverse with the horizontal line test 2. Replace f(x) by y 3. Interchange the roles of x and y and solve for y 4. Replace y with f^-1 in the new equation 5. Verify that f(f^-1(x)) = x = f^-1(f(x)) |
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Vertex/Standard form of a quadratic function |
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f(x) = a(x - h)^2 + k, a ≠ 0
where (h,k) is the vertex and x = h is the axis of symmetry |
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Vertical stretch by a factor of c |
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Vertical compression by a factor of 1/c |
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Horizontal stretch by a factor of 1/c if c > 0 |
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Horizontal compression by a factor of 1/c if 0 < c < 1 |
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f(x) = ax^2 + bx + c
tells us the y-intercept |
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f(x) = a(x - r)(x - s)
where r and s are the roots/zeros/x-intercepts |
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f(x) = x^2 + (bx/a) + (b/2a)^2 - (b/2a)^2 + (c/a)
f(x) = (x + (b/2a)^2) + ((4ac-b^2)/4a) |
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If n in a polynomial is even, |
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the ends of the graph will end going towards the same direction |
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If n is odd in a polynomial, |
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the ends of the graph will end going opposite directions |
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The highest possible number of zeros in a polynomial is |
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the highest power in the polynomial |
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The graph of f has at most ? turning points |
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when a zero is repeated
example: in f(x) = (x - 2)^2(x + 1)^3, 2 has a multiplicity of 2 and -1 has a multiplicity of 3 |
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Piece-wise defined function |
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When a graph is broken into pieces that have different equations |
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